What is the extreme (x^4-98x^2)/8 ?

The extreme (x^4-98x^2)/8 is Minimum(-7,-2401/8),Maximum(0,0),Minimum(7,-2401/8)

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extreme (x^4-98x^2)/8

extreme points

\frac{x ^{4} - 98 x ^{2}}{8}

Minimum (- 7, - \frac{2401}{8}), Maximum (0, 0), Minimum (7, - \frac{2401}{8})

Solution steps

f^{'} (x) = \frac{x ( x ^{2} - 49 )}{2}

Find intervals:

Decreasing

: - \infty < x < - 7,

Increasing

: - 7 < x < 0,

Decreasing

: 0 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 7

into

\frac{x ^{4} - 98 x ^{2}}{8} : - \frac{2401}{8}

Minimum (- 7, - \frac{2401}{8})

Plug

x = 0

into

\frac{x ^{4} - 98 x ^{2}}{8} : 0

Maximum (0, 0)

Plug

x = 7

into

\frac{x ^{4} - 98 x ^{2}}{8} : - \frac{2401}{8}

Minimum (7, - \frac{2401}{8})

Minimum (- 7, - \frac{2401}{8}), Maximum (0, 0), Minimum (7, - \frac{2401}{8})

2 x e^{3 x}

f (x, y) = 1 + x^{2} + x y + y^{2}

f (x, y) = 11 - x^{2} - y^{2}

f (x) = x^{2} - 25

U (X, Y) = X^{0.3} Y^{0.7}

What is the extreme (x^4-98x^2)/8 ?
The extreme (x^4-98x^2)/8 is Minimum(-7,-2401/8),Maximum(0,0),Minimum(7,-2401/8)