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Popular >

extreme f(x)=4x^2-16x

Solution

extreme points

f (x) = 4 x^{2} - 16 x

Solution

Minimum (2, - 16)

Solution steps

f^{'} (x) = 8 x - 16

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

4 x^{2} - 16 x : - 16

Minimum (2, - 16)

Graph

Popular Examples

extreme 2-2x^2 extreme points

2 - 2 x^{2}

extreme f(x,y)=10x^2-7y^2 extreme points

f (x, y) = 10 x^{2} - 7 y^{2}

extreme f(x)=-(4/(x^2))extreme points

f (x) = - (\frac{4}{x ^{2}})

extreme f(x)=x^3-27x+63 extreme points

f (x) = x^{3} - 27 x + 63

extreme f(x)=(8x)/(x^2+9),0<= x<= 9 extreme points

f (x) = \frac{8 x}{x ^{2} + 9}, 0 \leq x \leq 9

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2-16x ?
The extreme f(x)=4x^2-16x is Minimum(2,-16)