What is the extreme f(x)=x^3-27x+55 ?

The extreme f(x)=x^3-27x+55 is Maximum(-3,109),Minimum(3,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-27x+55

extreme points

f (x) = x^{3} - 27 x + 55

Maximum (- 3, 109), Minimum (3, 1)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 55 : 109

Maximum (- 3, 109)

Plug

x = 3

into

x^{3} - 27 x + 55 : 1

Minimum (3, 1)

Maximum (- 3, 109), Minimum (3, 1)

\frac{1}{2} x^{\frac{2}{3}} (2 x - 5)

f (x) = x + \frac{25}{x} + 4, 1 \leq x \leq 50

f (x, y) = 400 - 4 x^{2} - 81 y^{2}

f (x) = \frac{( x + 5 )}{x ^{2} - 2 x - 35}

f (x) = 2 x - 5 y + 3

What is the extreme f(x)=x^3-27x+55 ?
The extreme f(x)=x^3-27x+55 is Maximum(-3,109),Minimum(3,1)