What is the extreme (11-x)(x+1)^2 ?

The extreme (11-x)(x+1)^2 is Minimum(-1,0),Maximum(7,256)

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extreme (11-x)(x+1)^2

extreme points

(11 - x) (x + 1)^{2}

Minimum (- 1, 0), Maximum (7, 256)

Solution steps

f^{'} (x) = - 3 (x + 1) (x - 7)

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 7,

Decreasing

: 7 < x < \infty

Plug

x = - 1

into

(11 - x) (x + 1)^{2} : 0

Minimum (- 1, 0)

Plug

x = 7

into

(11 - x) (x + 1)^{2} : 256

Maximum (7, 256)

Minimum (- 1, 0), Maximum (7, 256)

f (x, y) = 2 x^{4} + 2 y^{4} - x y

f (x) = \frac{7}{2} x^{2} + \frac{7}{2} - 7 x - 4

\frac{2 ln ( x )}{x}

f (x) = x^{4} - 24 x^{2} + 64 x + 16

f (x) = \frac{4 x}{x ^{2} - 1}

What is the extreme (11-x)(x+1)^2 ?
The extreme (11-x)(x+1)^2 is Minimum(-1,0),Maximum(7,256)