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Popular >

extreme f(x)=(x^3)/(6x^2+4)

Solution

extreme points

f (x) = \frac{x ^{3}}{6 x ^{2} + 4}

Solution

Saddle (0, 0)

Solution steps

f^{'} (x) = \frac{3 x ^{2} ( x ^{2} + 2 )}{2 ( 3 x ^{2} + 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{3}}{6 x ^{2} + 4} : 0

Saddle (0, 0)

Graph

Popular Examples

extreme f(x,y)=x^2+y^2+2 extreme points

f (x, y) = x^{2} + y^{2} + 2

extreme f(x)=2x^3-x^2-4x-6 extreme points

f (x) = 2 x^{3} - x^{2} - 4 x - 6

extreme x^2+2y^2-2x-12y+19 extreme points

x^{2} + 2 y^{2} - 2 x - 12 y + 19

extreme f(x)=2x^3-x^2-4x+2 extreme points

f (x) = 2 x^{3} - x^{2} - 4 x + 2

extreme f(x)=2x^3-12x^2+18x+5 extreme points

f (x) = 2 x^{3} - 12 x^{2} + 18 x + 5

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^3)/(6x^2+4) ?
The extreme f(x)=(x^3)/(6x^2+4) is Saddle(0,0)