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Popular >

extreme f(x)=3x-x^2+40

Solution

extreme points

f (x) = 3 x - x^{2} + 40

Solution

Maximum (\frac{3}{2}, \frac{169}{4})

Solution steps

f^{'} (x) = - 2 x + 3

Find intervals:

Increasing

: - \infty < x < \frac{3}{2},

Decreasing

: \frac{3}{2} < x < \infty

Plug

x = \frac{3}{2}

into

3 x - x^{2} + 40 : \frac{169}{4}

Maximum (\frac{3}{2}, \frac{169}{4})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=3x-x^2+40 ?
The extreme f(x)=3x-x^2+40 is Maximum(3/2 , 169/4)