What is the extreme f(x)=cot(x)+10,-pi<= x<= pi/3 ?

The extreme f(x)=cot(x)+10,-pi<= x<= pi/3 is Minimum(pi/3 , 1/(sqrt(3))+10)

Popular >

extreme f(x)=cot(x)+10,-pi<= x<= pi/3

extreme points

f (x) = cot (x) + 10, - π \leq x \leq \frac{π}{3}

Minimum (\frac{π}{3}, \frac{1}{3} + 10)

Solution steps

Find the critical points:

x = \frac{π}{3}

Domain of

cot (x) + 10, - π \leq x \leq \frac{π}{3} : - π < x < 0 or 0 < x \leq \frac{π}{3}

Find intervals:

Decreasing

: - π < x < 0,

Decreasing

: 0 < x < \frac{π}{3}

Plug the extreme point

x = \frac{π}{3}

into

cot (x) + 10 \Rightarrow y = \frac{1}{3} + 10

Minimum (\frac{π}{3}, \frac{1}{3} + 10)

f (x, y) = x^{2} y + 2 x y - 2 x y^{2} + 2

f (x) = x^{4} + 4 x^{3} - 1

f (x, y) = x^{2} + x y + y^{2} - 31 y + 320

f (x, y) = 5 x + 3 y

f (x) = \frac{1}{( x ^{2} + 1 )}

What is the extreme f(x)=cot(x)+10,-pi<= x<= pi/3 ?
The extreme f(x)=cot(x)+10,-pi<= x<= pi/3 is Minimum(pi/3 , 1/(sqrt(3))+10)