What is the extreme f(x)=(x^2-4x+4)/(x-6) ?

The extreme f(x)=(x^2-4x+4)/(x-6) is Maximum(2,0),Minimum(10,16)

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extreme f(x)=(x^2-4x+4)/(x-6)

extreme points

f (x) = \frac{x ^{2} - 4 x + 4}{x - 6}

Maximum (2, 0), Minimum (10, 16)

Solution steps

f^{'} (x) = \frac{x ^{2} - 12 x + 20}{( x - 6 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 6,

Decreasing

: 6 < x < 10,

Increasing

: 10 < x < \infty

Plug

x = 2

into

\frac{x ^{2} - 4 x + 4}{x - 6} : 0

Maximum (2, 0)

Plug

x = 10

into

\frac{x ^{2} - 4 x + 4}{x - 6} : 16

Minimum (10, 16)

Maximum (2, 0), Minimum (10, 16)

f (x) = x^{3} - 588 x

\frac{3 x ^{3} + 3 x ^{2} - 6 x}{2 x ^{2} - 9 x - 5}

f (x) = (2 x^{2} - 8)^{2}

f (x) = 2 x^{3} - \frac{12 x ^{2}}{2} - 2

f (x) = 23 n - 166 n^{2}

What is the extreme f(x)=(x^2-4x+4)/(x-6) ?
The extreme f(x)=(x^2-4x+4)/(x-6) is Maximum(2,0),Minimum(10,16)