en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y= 1/(x^2-1)

Solution

extreme points

y = \frac{1}{x ^{2} - 1}

Solution

Maximum (0, - 1)

Solution steps

f^{'} (x) = - \frac{2 x}{( x ^{2} - 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

\frac{1}{x ^{2} - 1} : - 1

Maximum (0, - 1)

Graph

Popular Examples

extreme f(x,y)=(x^2-25)^2+(y^2-9)^2 extreme points

f (x, y) = (x^{2} - 25)^{2} + (y^{2} - 9)^{2}

extreme f(x)=6-|x|extreme points

f (x) = 6 - ∣ x ∣

extreme f(x)=4cos(2x)+1,(0,2pi)extreme points

f (x) = 4 cos (2 x) + 1, (0, 2 π)

extreme 2xy-5x^2-2y^2+4x+4y-4 extreme points

2 x y - 5 x^{2} - 2 y^{2} + 4 x + 4 y - 4

extreme f(x)=9xe^{-x}extreme points

f (x) = 9 x e^{- x}

Frequently Asked Questions (FAQ)

What is the extreme y= 1/(x^2-1) ?
The extreme y= 1/(x^2-1) is Maximum(0,-1)