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Popular >

extreme y=x^3-6x^2+2

Solution

extreme points

y = x^{3} - 6 x^{2} + 2

Solution

Maximum (0, 2), Minimum (4, - 30)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

x^{3} - 6 x^{2} + 2 : 2

Maximum (0, 2)

Plug

x = 4

into

x^{3} - 6 x^{2} + 2 : - 30

Minimum (4, - 30)

Maximum (0, 2), Minimum (4, - 30)

Graph

Popular Examples

extreme f(x)=x^3-3x+9 extreme points

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extreme f(x)=x^3-3x-4 extreme points

f (x) = x^{3} - 3 x - 4

extreme-5x^6ln(x)extreme points

- 5 x^{6} ln (x)

Frequently Asked Questions (FAQ)

What is the extreme y=x^3-6x^2+2 ?
The extreme y=x^3-6x^2+2 is Maximum(0,2),Minimum(4,-30)