What is the extreme F(x,y)=2x^5+x^3y^2+6xy^4 ?

The extreme F(x,y)=2x^5+x^3y^2+6xy^4 is None

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extreme F(x,y)=2x^5+x^3y^2+6xy^4

extreme points

F (x, y) = 2 x^{5} + x^{3} y^{2} + 6 x y^{4}

None

Solution steps

Find the critical points:

None

2 x^{5} + x^{3} y^{2} + 6 x y^{4}

has no critical points, therefore there are no extreme points

None

f (x) = \frac{9 x}{x ^{2} + 9}

f (x) = - 6 x^{2} + 30 x - 36

f (x) = x^{3} + 3 x y - y^{3}

f (x, y) = - 8 x y + 2 x^{4} + 2 y^{4}

f (x) = 2 x - sin (x), 0 \leq x \leq π

What is the extreme F(x,y)=2x^5+x^3y^2+6xy^4 ?
The extreme F(x,y)=2x^5+x^3y^2+6xy^4 is None