What is the extreme f(x)=x^2+y^2-6xy+3x+6y-2 ?

The extreme f(x)=x^2+y^2-6xy+3x+6y-2 is Saddle(21/16 , 15/16)

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extreme f(x)=x^2+y^2-6xy+3x+6y-2

extreme points

f (x) = x^{2} + y^{2} - 6 x y + 3 x + 6 y - 2

Saddle (\frac{21}{16}, \frac{15}{16})

Solution steps

Find the critical points:

(\frac{21}{16}, \frac{15}{16})

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = - 32

Check the sign of at each critical point

Check critical point

(\frac{21}{16}, \frac{15}{16}) :

Saddle

Saddle (\frac{21}{16}, \frac{15}{16})

f (x, y, z) = z

- 3^{2 x - 4} - 5

f (x) = (8 x - 9) e^{4 x}

y = 6 x e^{- x^{2}}

2 x^{2} + y^{2}

What is the extreme f(x)=x^2+y^2-6xy+3x+6y-2 ?
The extreme f(x)=x^2+y^2-6xy+3x+6y-2 is Saddle(21/16 , 15/16)