What is the extreme f(x)=(4(x-10)^2)/(x-6),(0,6) ?

The extreme f(x)=(4(x-10)^2)/(x-6),(0,6) is Maximum(2,-64)

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extreme f(x)=(4(x-10)^2)/(x-6),(0,6)

extreme points

f (x) = \frac{4 ( x - 10 ) ^{2}}{x - 6}, (0, 6)

Maximum (2, - 64)

Solution steps

Find the critical points:

x = 2

Domain of

\frac{4 ( x - 10 ) ^{2}}{x - 6}, (0, 6) : 0 < x < 6

Find intervals:

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < 6

Plug the extreme point

x = 2

into

\frac{4 ( x - 10 ) ^{2}}{x - 6} \Rightarrow y = - 64

Maximum (2, - 64)

f (x) = 15 x^{\frac{2}{3}} - x

f (x, y) = x^{2} + 2 x + y^{2} - 2 y + 2

f (x, y) = x^{2} + 2 x y - x y^{2}

y = \frac{x ^{2} - 9 x + 39}{x - 7}

\frac{1}{( x + 1 ) ^{2}}

What is the extreme f(x)=(4(x-10)^2)/(x-6),(0,6) ?
The extreme f(x)=(4(x-10)^2)/(x-6),(0,6) is Maximum(2,-64)