What is the extreme f(x)=x^3-5x^2-8x ?

The extreme f(x)=x^3-5x^2-8x is Maximum(-2/3 , 76/27),Minimum(4,-48)

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extreme f(x)=x^3-5x^2-8x

extreme points

f (x) = x^{3} - 5 x^{2} - 8 x

Maximum (- \frac{2}{3}, \frac{76}{27}), Minimum (4, - 48)

Solution steps

f^{'} (x) = 3 x^{2} - 10 x - 8

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 5 x^{2} - 8 x : \frac{76}{27}

Maximum (- \frac{2}{3}, \frac{76}{27})

Plug

x = 4

into

x^{3} - 5 x^{2} - 8 x : - 48

Minimum (4, - 48)

Maximum (- \frac{2}{3}, \frac{76}{27}), Minimum (4, - 48)

f (x, y) = - 2 y - 3 x + 6

f (x) = \frac{( x - 2 ) ^{2}}{x + 6}

f (x) = cot (x) + tan (x)

f (x) = x^{3} + y^{3} + 4 x y

f (x) = 6 x - 24

What is the extreme f(x)=x^3-5x^2-8x ?
The extreme f(x)=x^3-5x^2-8x is Maximum(-2/3 , 76/27),Minimum(4,-48)