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Popular >

extreme h(x)=2(x-5)^3

Solution

extreme points

h (x) = 2 (x - 5)^{3}

Solution

Saddle (5, 0)

Solution steps

f^{'} (x) = 6 (x - 5)^{2}

Find intervals:

Increasing

: - \infty < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

2 (x - 5)^{3} : 0

Saddle (5, 0)

Graph

Popular Examples

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f (x, y) = x^{2} + 2 y^{2} - x y + 3 x + 2 y

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f (x) = - 5 x^{3} + 15 x + 6

extreme f(x,y)=(x-5)(30-6x+4y)+(y-12)(80+8x-7y)extreme points

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f (x) = - 0.001 x^{2} + 3.4 x - 40

extreme (sin(5x))/(sin^5(x))extreme points

\frac{sin ( 5 x )}{sin ^{5} ( x )}

Frequently Asked Questions (FAQ)

What is the extreme h(x)=2(x-5)^3 ?
The extreme h(x)=2(x-5)^3 is Saddle(5,0)