What is the extreme f(x)=(sqrt(4y+7))/(3-x) ?

The extreme f(x)=(sqrt(4y+7))/(3-x) is None

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extreme f(x)=(sqrt(4y+7))/(3-x)

extreme points

f (x) = \frac{4 y + 7}{3 - x}

None

Solution steps

Find the critical points:

None

\frac{4 y + 7}{3 - x}

has no critical points, therefore there are no extreme points

None

3 cos^{2} (x), 0 \leq x \leq π

f (x) = x + \frac{9}{x} + 2, 1 \leq x \leq 18

f (x) = 7 x^{4} - 6 x^{2} - 1

x^{2} - 2 x y + y^{3} - y

f (x) = 4 x + \frac{4}{x}

What is the extreme f(x)=(sqrt(4y+7))/(3-x) ?
The extreme f(x)=(sqrt(4y+7))/(3-x) is None