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Popular >

extreme f(x)=x^2+6x+16

Solution

extreme points

f (x) = x^{2} + 6 x + 16

Solution

Minimum (- 3, 7)

Solution steps

f^{'} (x) = 2 x + 6

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

x^{2} + 6 x + 16 : 7

Minimum (- 3, 7)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+6x+16 ?
The extreme f(x)=x^2+6x+16 is Minimum(-3,7)