What is the extreme f(x)=[2-x],-2<= x<= 2 ?

The extreme f(x)=[2-x],-2<= x<= 2 is Maximum(-2,4),Minimum(2,0)

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extreme f(x)=[2-x],-2<= x<= 2

extreme points

f (x) = [2 - x], - 2 \leq x \leq 2

Maximum (- 2, 4), Minimum (2, 0)

Solution steps

Find the critical points:

x = - 2, x = 2

Domain of

2 - x, - 2 \leq x \leq 2 : - 2 \leq x \leq 2

Find intervals:

Decreasing

: - 2 < x < 2

Plug the extreme point

x = - 2

into

2 - x \Rightarrow y = 4

Maximum (- 2, 4)

Plug the extreme point

x = 2

into

2 - x \Rightarrow y = 0

Minimum (2, 0)

Maximum (- 2, 4), Minimum (2, 0)

\frac{x ^{3}}{1 + x ^{2}}

f (x) = ((x^{2} + y^{2}) (e^{y^{2} - x^{2}}))

f (x) = - 1

f (x, y) = 3 - x + 4 x^{2} - 2 x y + y^{2} + x^{3} + 5 x y^{2}

f (x) = 2 x^{3} - 36 x^{2} + 120 x + 2

What is the extreme f(x)=[2-x],-2<= x<= 2 ?
The extreme f(x)=[2-x],-2<= x<= 2 is Maximum(-2,4),Minimum(2,0)