What is the extreme f(x)=4x^3+21x^2+36x-20 ?

The extreme f(x)=4x^3+21x^2+36x-20 is Maximum(-2,-40),Minimum(-3/2 ,-161/4)

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extreme f(x)=4x^3+21x^2+36x-20

extreme points

f (x) = 4 x^{3} + 21 x^{2} + 36 x - 20

Maximum (- 2, - 40), Minimum (- \frac{3}{2}, - \frac{161}{4})

Solution steps

f^{'} (x) = 12 x^{2} + 42 x + 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < - \frac{3}{2},

Increasing

: - \frac{3}{2} < x < \infty

Plug

x = - 2

into

4 x^{3} + 21 x^{2} + 36 x - 20 : - 40

Maximum (- 2, - 40)

Plug

x = - \frac{3}{2}

into

4 x^{3} + 21 x^{2} + 36 x - 20 : - \frac{161}{4}

Minimum (- \frac{3}{2}, - \frac{161}{4})

Maximum (- 2, - 40), Minimum (- \frac{3}{2}, - \frac{161}{4})

\frac{x ^{2} - 15}{x - 4}

f (x) = e^{x}, 0 \leq x \leq ln (18)

f (x) = 2 x^{3} - 6 x^{2} - 210 x + 7

f (x) = - 3 x^{5} + 5 x^{3} + 1

f (x) = - 2 + x - x^{2}

What is the extreme f(x)=4x^3+21x^2+36x-20 ?
The extreme f(x)=4x^3+21x^2+36x-20 is Maximum(-2,-40),Minimum(-3/2 ,-161/4)