What is the extreme f(x)=2x^{-3}-x^{-2} ?

The extreme f(x)=2x^{-3}-x^{-2} is Minimum(3,-1/27)

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extreme f(x)=2x^{-3}-x^{-2}

extreme points

f (x) = 2 x^{- 3} - x^{- 2}

Minimum (3, - \frac{1}{27})

Solution steps

f^{'} (x) = - \frac{6}{x ^{4}} + \frac{2}{x ^{3}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 3

into

2 x^{- 3} - x^{- 2} : - \frac{1}{27}

Minimum (3, - \frac{1}{27})

f (x) = \frac{x ^{6}}{6} - ln (x)

f (x) = 4 x^{3} - 4 x^{2} - 4 x + 6, - 1 \leq x \leq 2

f (x) = cos (x) - 5 x, 0 \leq x \leq 4 π

4 x^{3} - 6 x

y \cdot ln (x) + y

What is the extreme f(x)=2x^{-3}-x^{-2} ?
The extreme f(x)=2x^{-3}-x^{-2} is Minimum(3,-1/27)