What is the extreme f(x)=(x^2+7)(49+x^2) ?

The extreme f(x)=(x^2+7)(49+x^2) is Minimum(0,343)

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extreme f(x)=(x^2+7)(49+x^2)

extreme points

f (x) = (x^{2} + 7) (49 + x^{2})

Minimum (0, 343)

Solution steps

f^{'} (x) = 4 x (x^{2} + 28)

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

(x^{2} + 7) (49 + x^{2}) : 343

Minimum (0, 343)

f (x) = x^{4} - 6 x^{2} + 8 x

f (x) = \frac{x ^{3}}{3} - \frac{x ^{2}}{4} - 5 x + 5

f (x) = 6 x^{3} + x^{2} - 2

f (x, y) = x^{2} - 4 x y + 5 y^{2} + 2 x + 4 y - 4

f (x) = 1 + \frac{1}{x} + \frac{9}{x ^{2}} + \frac{1}{x ^{3}}

What is the extreme f(x)=(x^2+7)(49+x^2) ?
The extreme f(x)=(x^2+7)(49+x^2) is Minimum(0,343)