What is the extreme f(x)=3x^4-7ln(x) ?

The extreme f(x)=3x^4-7ln(x) is Minimum(\sqrt[4]{7/12}, 7/4-7/4 ln(7/12))

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extreme f(x)=3x^4-7ln(x)

extreme points

f (x) = 3 x^{4} - 7 ln (x)

Solution steps

f^{'} (x) = 12 x^{3} - \frac{7}{x}

Find intervals:

Decreasing

Increasing

Plug

into

3 x^{4} - 7 ln (x) : \frac{7}{4} - \frac{7}{4} ln (\frac{7}{12})

f (x, y) = ln (9 x^{2} + 3 y^{2} - 4)

f (x) = 3 x^{\frac{2}{3}} - 7

f (x, y) = \frac{1}{x + y + 3}

f (x, y) = x y + x^{2} y + x y^{2}

\frac{x ^{2} + 1}{x ^{3} - 1}

What is the extreme f(x)=3x^4-7ln(x) ?
The extreme f(x)=3x^4-7ln(x) is Minimum(\sqrt[4]{7/12}, 7/4-7/4 ln(7/12))