What is the extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6) ?

The extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6) is Minimum(-7,0)

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extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6)

extreme points

f (x) = \frac{2 ( x + 7 ) ^{2}}{x + 10}, (- 10, - 6)

Minimum (- 7, 0)

Solution steps

Find the critical points:

x = - 7

Domain of

\frac{2 ( x + 7 ) ^{2}}{x + 10}, (- 10, - 6) : - 10 < x < - 6

Find intervals:

Decreasing

: - 10 < x < - 7,

Increasing

: - 7 < x < - 6

Plug the extreme point

x = - 7

into

\frac{2 ( x + 7 ) ^{2}}{x + 10} \Rightarrow y = 0

Minimum (- 7, 0)

f (x, y) = x^{6} - 3 x^{2} y^{2} + 3 x y^{3}

- x^{3} + x^{2} + 8 x + 8

f (x) = - 3 x^{3} + 27 x

F (X, Y) = 3 X + 2 X^{2} + 4 Y + Y^{2} - 2 X Y

f (x) = 8 x^{2} - 6 x^{4}

What is the extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6) ?
The extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6) is Minimum(-7,0)