What is the extreme f(x)=((x^2-11))/(x+6) ?

The extreme f(x)=((x^2-11))/(x+6) is Maximum(-11,-22),Minimum(-1,-2)

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extreme f(x)=((x^2-11))/(x+6)

extreme points

f (x) = \frac{( x ^{2} - 11 )}{x + 6}

Maximum (- 11, - 22), Minimum (- 1, - 2)

Solution steps

f^{'} (x) = \frac{x ^{2} + 12 x + 11}{( x + 6 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 11,

Decreasing

: - 11 < x < - 6,

Decreasing

: - 6 < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 11

into

\frac{x ^{2} - 11}{x + 6} : - 22

Maximum (- 11, - 22)

Plug

x = - 1

into

\frac{x ^{2} - 11}{x + 6} : - 2

Minimum (- 1, - 2)

Maximum (- 11, - 22), Minimum (- 1, - 2)

\frac{64}{x ^{2} + 6 x - 7}

f (x) = 6 x e^{- x^{2}}

f (x) = \frac{- 2}{x - 3}

y = x^{3} - 12 x + 3

y = - x - ln ∣ x ∣

What is the extreme f(x)=((x^2-11))/(x+6) ?
The extreme f(x)=((x^2-11))/(x+6) is Maximum(-11,-22),Minimum(-1,-2)