What is the extreme f(x)=x^3-48x+9 ?

The extreme f(x)=x^3-48x+9 is Maximum(-4,137),Minimum(4,-119)

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extreme f(x)=x^3-48x+9

extreme points

f (x) = x^{3} - 48 x + 9

Maximum (- 4, 137), Minimum (4, - 119)

Solution steps

f^{'} (x) = 3 x^{2} - 48

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

x^{3} - 48 x + 9 : 137

Maximum (- 4, 137)

Plug

x = 4

into

x^{3} - 48 x + 9 : - 119

Minimum (4, - 119)

Maximum (- 4, 137), Minimum (4, - 119)

f (x, y) = x^{2} y^{2} + 3 x y + 4 x

f (x, y) = \frac{y}{x} - ln (x) + \frac{1}{2} y^{2}

x^{2} + 2 x + 5

f (x) = 420 t - 35 t

f (x) = x^{2} - 25

What is the extreme f(x)=x^3-48x+9 ?
The extreme f(x)=x^3-48x+9 is Maximum(-4,137),Minimum(4,-119)