What is the extreme f(x)=-4x^4+3x^2-15x+5 ?

The extreme f(x)=-4x^4+3x^2-15x+5 is Maximum(-1.10580…,19.27448…)

Popular >

extreme f(x)=-4x^4+3x^2-15x+5

extreme points

f (x) = - 4 x^{4} + 3 x^{2} - 15 x + 5

Maximum (- 1.10580 \dots, 19.27448 \dots)

Solution steps

Find the critical points:

x \approx - 1.10580 \dots

Domain of

- 4 x^{4} + 3 x^{2} - 15 x + 5 : - \infty < x < \infty

Find intervals:

Increasing

: - \infty < x < - 1.10580 \dots,

Decreasing

: - 1.10580 \dots < x < \infty

Plug the extreme point

x = - 1.10580 \dots

into

- 4 x^{4} + 3 x^{2} - 15 x + 5 \Rightarrow y = 19.27448 \dots

Maximum (- 1.10580 \dots, 19.27448 \dots)

f (x) = x^{2} + 3 - x

2 x^{2} - 7 x - 9

\frac{2}{3} x^{3} - \frac{39}{2} x^{2} + 19 x, [0 \leq x \leq 1]

\frac{3 + x}{9 - x}

f (x) = 3 x^{3} e^{- x}, - 1 \leq x \leq 4

What is the extreme f(x)=-4x^4+3x^2-15x+5 ?
The extreme f(x)=-4x^4+3x^2-15x+5 is Maximum(-1.10580…,19.27448…)