What is the extreme f(x)=9x^{2/3}-x ?

The extreme f(x)=9x^{2/3}-x is Minimum(0,0),Maximum(216,108)

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extreme f(x)=9x^{2/3}-x

extreme points

f (x) = 9 x^{\frac{2}{3}} - x

Minimum (0, 0), Maximum (216, 108)

Solution steps

f^{'} (x) = \frac{6}{x ^{\frac{1}{3}}} - 1

Find intervals:

Decreasing

: - \infty < x < \frac{1}{216},

Increasing

: \frac{1}{216} < x < \infty

Plug

x = 0

into

9 x^{\frac{2}{3}} - x : 0

Minimum (0, 0)

Plug

x = 216

into

9 x^{\frac{2}{3}} - x : 108

Maximum (216, 108)

Minimum (0, 0), Maximum (216, 108)

f (x, y) = x^{2} - x y + y^{2} + 2 x + 2 y - 4

x + 3, 0 < x < 2

f (x) = x + 4 - x

f (x) = 3 x^{4} - 4 x^{3} - 12 x^{2} - 7

f (x, y) = e^{y} (4 x^{2} + 2 x y + y^{2} - 6 x - 15)

What is the extreme f(x)=9x^{2/3}-x ?
The extreme f(x)=9x^{2/3}-x is Minimum(0,0),Maximum(216,108)