What is the extreme y=cos(x) ?

The extreme y=cos(x) is Maximum(2pin,1),Minimum(pi+2pin,-1)

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extreme y=cos(x)

extreme points

y = cos (x)

Maximum (2 πn, 1), Minimum (π + 2 πn, - 1)

Solution steps

Find the critical points:

x = 2 πn, x = π + 2 πn

Domain of

cos (x) : - \infty < x < \infty

Find intervals:

Decreasing

: 2 πn < x < π + 2 πn,

Increasing

: π + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = 2 πn

into

cos (x) \Rightarrow y = 1

Maximum (2 πn, 1)

Plug the extreme point

x = π + 2 πn

into

cos (x) \Rightarrow y = - 1

Minimum (π + 2 πn, - 1)

Maximum (2 πn, 1), Minimum (π + 2 πn, - 1)

2 x^{2} + 24 x - 6

f (x, y) = ((\frac{( 1 - x )}{x}) y)

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 6

f (x) = x^{\frac{4}{3}}, - 1 \leq x \leq 8

f (x, y) = (x + y - 1) \cdot x y

What is the extreme y=cos(x) ?
The extreme y=cos(x) is Maximum(2pin,1),Minimum(pi+2pin,-1)