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Popular >

extreme f(x)=(4x^2)/(x^2+3)

Solution

extreme points

f (x) = \frac{4 x ^{2}}{x ^{2} + 3}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{24 x}{( x ^{2} + 3 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{4 x ^{2}}{x ^{2} + 3} : 0

Minimum (0, 0)

Graph

Popular Examples

extreme y=2x^3-3x^2-12x+1 extreme points

y = 2 x^{3} - 3 x^{2} - 12 x + 1

extreme f(x)=7x^{2/3}extreme points

f (x) = 7 x^{\frac{2}{3}}

extreme x^4+x^3-3x^2+1 extreme points

x^{4} + x^{3} - 3 x^{2} + 1

extreme f(x)=-(x-1)^2+4 extreme points

f (x) = - (x - 1)^{2} + 4

extreme f(x)=x^3-7x+1 extreme points

f (x) = x^{3} - 7 x + 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(4x^2)/(x^2+3) ?
The extreme f(x)=(4x^2)/(x^2+3) is Minimum(0,0)