What is the extreme f(x)=2x^3-6x^2-48x+9 ?

The extreme f(x)=2x^3-6x^2-48x+9 is Maximum(-2,65),Minimum(4,-151)

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extreme f(x)=2x^3-6x^2-48x+9

extreme points

f (x) = 2 x^{3} - 6 x^{2} - 48 x + 9

Maximum (- 2, 65), Minimum (4, - 151)

Solution steps

f^{'} (x) = 6 x^{2} - 12 x - 48

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 2

into

2 x^{3} - 6 x^{2} - 48 x + 9 : 65

Maximum (- 2, 65)

Plug

x = 4

into

2 x^{3} - 6 x^{2} - 48 x + 9 : - 151

Minimum (4, - 151)

Maximum (- 2, 65), Minimum (4, - 151)

y = x^{2} - 3 x + 2

f (x) = - \frac{2}{5} x^{\frac{5}{2}} + 32 x^{\frac{1}{2}}

f (x) = (\frac{- 2 x}{x ^{2} + 7})

f (x, y) = (x^{2} - 8 x) (y^{2} - 3 y)

F (x) = \frac{5 x ^{2}}{x ^{2} - 16}

What is the extreme f(x)=2x^3-6x^2-48x+9 ?
The extreme f(x)=2x^3-6x^2-48x+9 is Maximum(-2,65),Minimum(4,-151)