What is the extreme 16(-1/(x^2)-2/(x^3)) ?

The extreme 16(-1/(x^2)-2/(x^3)) is Minimum(-3,-16/27)

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extreme 16(-1/(x^2)-2/(x^3))

extreme points

16 (- \frac{1}{x ^{2}} - \frac{2}{x ^{3}})

Minimum (- 3, - \frac{16}{27})

Solution steps

f^{'} (x) = 16 (\frac{2}{x ^{3}} + \frac{6}{x ^{4}})

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 3

into

16 (- \frac{1}{x ^{2}} - \frac{2}{x ^{3}}) : - \frac{16}{27}

Minimum (- 3, - \frac{16}{27})

f (x, y) = x^{2} + x y + y^{2} - 22 y + 161

f (x) = 3 x^{6} - 7 x^{5}

f (x, y) = e^{x^{2} + 3 y^{2} + 15}

g (x) = x^{3} - 2 x^{2} - 4 x + 8

f (x) = x^{3} + 6 x^{2} - 63 x + 5, - 8 \leq x \leq 0

What is the extreme 16(-1/(x^2)-2/(x^3)) ?
The extreme 16(-1/(x^2)-2/(x^3)) is Minimum(-3,-16/27)