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Popular >

extreme f(x)=x^2+7x-1

Solution

extreme points

f (x) = x^{2} + 7 x - 1

Solution

Minimum (- \frac{7}{2}, - \frac{53}{4})

Solution steps

f^{'} (x) = 2 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{2},

Increasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

x^{2} + 7 x - 1 : - \frac{53}{4}

Minimum (- \frac{7}{2}, - \frac{53}{4})

Popular Examples

extreme f(x)=-3x^3+3x^2-x-5 extreme points

f (x) = - 3 x^{3} + 3 x^{2} - x - 5

extreme 5x^{2/3}-x^{1/3}extreme points

5 x^{\frac{2}{3}} - x^{\frac{1}{3}}

extreme 2sin^2(x)extreme points

2 sin^{2} (x)

extreme f(x,y)=x^2+x-3xy+y^3-5 extreme points

f (x, y) = x^{2} + x - 3 x y + y^{3} - 5

extreme y=5-2x^2,-4<= x<= 2 extreme points

y = 5 - 2 x^{2}, - 4 \leq x \leq 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+7x-1 ?
The extreme f(x)=x^2+7x-1 is Minimum(-7/2 ,-53/4)