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Popular >

extreme (8-x)(x+1)^2

Solution

extreme points

(8 - x) (x + 1)^{2}

Solution

Minimum (- 1, 0), Maximum (5, 108)

Solution steps

f^{'} (x) = - 3 (x + 1) (x - 5)

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = - 1

into

(8 - x) (x + 1)^{2} : 0

Minimum (- 1, 0)

Plug

x = 5

into

(8 - x) (x + 1)^{2} : 108

Maximum (5, 108)

Minimum (- 1, 0), Maximum (5, 108)

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Frequently Asked Questions (FAQ)

What is the extreme (8-x)(x+1)^2 ?
The extreme (8-x)(x+1)^2 is Minimum(-1,0),Maximum(5,108)