What is the extreme f(x)=8(1+1/x+1/(x^2)) ?

The extreme f(x)=8(1+1/x+1/(x^2)) is Minimum(-2,6)

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extreme f(x)=8(1+1/x+1/(x^2))

extreme points

f (x) = 8 (1 + \frac{1}{x} + \frac{1}{x ^{2}})

Minimum (- 2, 6)

Solution steps

f^{'} (x) = 8 (- \frac{1}{x ^{2}} - \frac{2}{x ^{3}})

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 2

into

8 (1 + \frac{1}{x} + \frac{1}{x ^{2}}) : 6

Minimum (- 2, 6)

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What is the extreme f(x)=8(1+1/x+1/(x^2)) ?
The extreme f(x)=8(1+1/x+1/(x^2)) is Minimum(-2,6)