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Popular >

extreme y= 1/3 x^2+2x+5

Solution

extreme points

y = \frac{1}{3} x^{2} + 2 x + 5

Solution

Minimum (- 3, 2)

Solution steps

f^{'} (x) = \frac{2 x}{3} + 2

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

\frac{1}{3} x^{2} + 2 x + 5 : 2

Minimum (- 3, 2)

Popular Examples

extreme f(x)=2x^2+8y^2 extreme points

f (x) = 2 x^{2} + 8 y^{2}

extreme f(x)=3x^5-25x^3+60x+1 extreme points

f (x) = 3 x^{5} - 25 x^{3} + 60 x + 1

extreme f(x)=-7x^2-5y^2+14x+10y-2 extreme points

f (x) = - 7 x^{2} - 5 y^{2} + 14 x + 10 y - 2

extreme x^4+8x^3-14x^2 extreme points

x^{4} + 8 x^{3} - 14 x^{2}

extreme f(x)=5x^2-30x,0<= x<= 5 extreme points

f (x) = 5 x^{2} - 30 x, 0 \leq x \leq 5

Frequently Asked Questions (FAQ)

What is the extreme y= 1/3 x^2+2x+5 ?
The extreme y= 1/3 x^2+2x+5 is Minimum(-3,2)