en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-3x^2+3x-1

Solution

extreme points

f (x) = x^{3} - 3 x^{2} + 3 x - 1

Solution

Saddle (1, 0)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x + 3

Find intervals:

Increasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{3} - 3 x^{2} + 3 x - 1 : 0

Saddle (1, 0)

Popular Examples

extreme f(x)=4x^5-7x^2+8 extreme points

f (x) = 4 x^{5} - 7 x^{2} + 8

extreme f(x)= x/(x^2+1),(-1,2)extreme points

f (x) = \frac{x}{x ^{2} + 1}, (- 1, 2)

extreme f(x)=5x^3+x^4 extreme points

f (x) = 5 x^{3} + x^{4}

extreme f(x)=9x^2-4x extreme points

f (x) = 9 x^{2} - 4 x

extreme f(x)=-(x+1)^2*(x+3)^3*(x-4)^2 extreme points

f (x) = - (x + 1)^{2} \cdot (x + 3)^{3} \cdot (x - 4)^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3-3x^2+3x-1 ?
The extreme f(x)=x^3-3x^2+3x-1 is Saddle(1,0)