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Popular >

extreme f(x)=x^6-2x^5+8x^4

Solution

extreme points

f (x) = x^{6} - 2 x^{5} + 8 x^{4}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = 6 x^{5} - 10 x^{4} + 32 x^{3}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{6} - 2 x^{5} + 8 x^{4} : 0

Minimum (0, 0)

Popular Examples

extreme f(x)=12x^3-x^4=x^3(12-x)extreme points

f (x) = 12 x^{3} - x^{4} = x^{3} (12 - x)

solvefor x,f=y^2-xy-x^2 solve for

x, f = y^{2} - x y - x^{2}

extreme f(x)=x^3+2x^2+6x+6 extreme points

f (x) = x^{3} + 2 x^{2} + 6 x + 6

extreme y=x^3(x-5)^2 extreme points

y = x^{3} (x - 5)^{2}

extreme x/(2-x)extreme points

\frac{x}{2 - x}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^6-2x^5+8x^4 ?
The extreme f(x)=x^6-2x^5+8x^4 is Minimum(0,0)