What is the extreme f(x)=-5x+2ln(2x) ?

The extreme f(x)=-5x+2ln(2x) is Maximum(2/5 ,-2+2ln(4/5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-5x+2ln(2x)

extreme points

f (x) = - 5 x + 2 ln (2 x)

Maximum (\frac{2}{5}, - 2 + 2 ln (\frac{4}{5}))

Solution steps

f^{'} (x) = - 5 + \frac{2}{x}

Find intervals:

Increasing

: 0 < x < \frac{2}{5},

Decreasing

: \frac{2}{5} < x < \infty

Plug

x = \frac{2}{5}

into

- 5 x + 2 ln (2 x) : - 2 + 2 ln (\frac{4}{5})

Maximum (\frac{2}{5}, - 2 + 2 ln (\frac{4}{5}))

\frac{x + 3}{x ^{2} - 2 x - 15}

f (x, y) = - (x + 1) 2 - (y + x) 2

f (x) = 2 x^{3} - 36 x^{2} + 192 x, 3 \leq x \leq 9

f (x) = 2 x^{2} - 3 x - 5

y = 4 x + 4 sin (x), 0 \leq x \leq 2 π

What is the extreme f(x)=-5x+2ln(2x) ?
The extreme f(x)=-5x+2ln(2x) is Maximum(2/5 ,-2+2ln(4/5))