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Popular >

extreme f(x)=(x-1)^3+4

Solution

extreme points

f (x) = (x - 1)^{3} + 4

Solution

Saddle (1, 4)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x + 3

Find intervals:

Increasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

(x - 1)^{3} + 4 : 4

Saddle (1, 4)

Graph

Popular Examples

extreme f(x)=-2x^4+x^3+6x^2+2x-5 extreme points

f (x) = - 2 x^{4} + x^{3} + 6 x^{2} + 2 x - 5

extreme f(x)=x^3-3x^2-24x-2 extreme points

f (x) = x^{3} - 3 x^{2} - 24 x - 2

extreme f(x)=-2x^3-9x^2 extreme points

f (x) = - 2 x^{3} - 9 x^{2}

extreme f(x)=sin(x)+cos(2x)extreme points

f (x) = sin (x) + cos (2 x)

extreme f(x)= 1/2 extreme points

f (x) = \frac{1}{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x-1)^3+4 ?
The extreme f(x)=(x-1)^3+4 is Saddle(1,4)