What is the extreme S(v,t)=v*2t-v/t*(2t^2)/2 ?

The extreme S(v,t)=v*2t-v/t*(2t^2)/2 is Saddle(0,0)

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extreme S(v,t)=v2t-v/t(2t^2)/2

extreme points

S (v, t) = v \cdot 2 t - \frac{v}{t} \cdot \frac{2 t ^{2}}{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial v ^{2}} = 0

D (v, t) = - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x, y) = 4 x^{2} - 3 y^{2} + 3 x - 4 y + 6

f (x) = 5 (4 x)^{x}, 0.05 \leq x \leq 1

Q (t) = 200 + 100 e^{k t}

4 x y + x^{4} + y^{4}

y = x^{3} - 3 x^{2} - 9 x + 1

What is the extreme S(v,t)=v*2t-v/t*(2t^2)/2 ?
The extreme S(v,t)=v*2t-v/t*(2t^2)/2 is Saddle(0,0)