What is the extreme Q(t)=200+100e^{kt} ?

The extreme Q(t)=200+100e^{kt} is Saddle(0,0)

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extreme Q(t)=200+100e^{kt}

extreme points

Q (t) = 200 + 100 e^{k t}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial t ^{2}} = 100 e^{t k} t^{2}

D (t, k) = - 20000 e^{2 t k} t k - 10000 e^{2 t k}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

4 x y + x^{4} + y^{4}

y = x^{3} - 3 x^{2} - 9 x + 1

f (x, y) = x (2 y^{2} + x^{2}) - 4 (x^{2} + y^{2}) + e^{b}

y = \frac{9 x}{x ^{2} + 1}

f (x, y) = 2 x^{2} + 2 x y + 5 y^{2} + 2 x - 2 y + 1

What is the extreme Q(t)=200+100e^{kt} ?
The extreme Q(t)=200+100e^{kt} is Saddle(0,0)