en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^2+4x+7

Solution

extreme points

f (x) = x^{2} + 4 x + 7

Solution

Minimum (- 2, 3)

Solution steps

f^{'} (x) = 2 x + 4

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

x^{2} + 4 x + 7 : 3

Minimum (- 2, 3)

Popular Examples

extreme (2-x)/(x+4)extreme points

\frac{2 - x}{x + 4}

extreme f(x,y)=6-x^2-6x-y^2 extreme points

f (x, y) = 6 - x^{2} - 6 x - y^{2}

extreme f(x,y)=2xy-5x^2-2y^2+4x+4y-4 extreme points

f (x, y) = 2 x y - 5 x^{2} - 2 y^{2} + 4 x + 4 y - 4

extreme y=-2x^2+10x+1 extreme points

y = - 2 x^{2} + 10 x + 1

extreme f(x)=x+cos(x),-2pi<= x<= 2pi extreme points

f (x) = x + cos (x), - 2 π \leq x \leq 2 π

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+4x+7 ?
The extreme f(x)=x^2+4x+7 is Minimum(-2,3)