en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^4-24^2+180

Solution

extreme points

f (x) = x^{4} - 2 4^{2} + 180

Solution

Minimum (0, - 396)

Solution steps

f^{'} (x) = 4 x^{3}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{4} - 2 4^{2} + 180 : - 396

Minimum (0, - 396)

Popular Examples

extreme f(x)=2x^4-16x^3 extreme points

f (x) = 2 x^{4} - 16 x^{3}

extreme f(x)=x^2-8x,0<= x<= 9 extreme points

f (x) = x^{2} - 8 x, 0 \leq x \leq 9

extreme f(x)=2-3x,0<= x<= 1 extreme points

f (x) = 2 - 3 x, 0 \leq x \leq 1

extreme f(x)=(1/12 x^3+(-1)/2 x^2+12)extreme points

f (x) = (\frac{1}{12} x^{3} + \frac{- 1}{2} x^{2} + 12)

extreme y=x^2+4x-7 extreme points

y = x^{2} + 4 x - 7

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4-24^2+180 ?
The extreme f(x)=x^4-24^2+180 is Minimum(0,-396)