What is the extreme f(x)= 1/x ,[1,infinity ] ?

The extreme f(x)= 1/x ,[1,infinity ] is Maximum(1,1)

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extreme f(x)= 1/x ,[1,infinity ]

extreme points

f (x) = \frac{1}{x}, [1, \infty]

Maximum (1, 1)

Solution steps

Find the critical points:

x = 1

Domain of

\frac{1}{x}, [1, \infty] : x \geq 1

Find intervals:

Decreasing

: 1 < x < \infty

Plug the extreme point

x = 1

into

\frac{1}{x} \Rightarrow y = 1

Maximum (1, 1)

f (x) = - 0.1 x^{2} + 1.4 x + 98.9

f (x, y) = 6 y^{2} + 4 x^{2} + 4 x y - 16 y + 8 x

y = (lo g_{10} (5 x)) + (3 I n x^{3})

x^{2} + \frac{640}{x}

f (x) = 2 x^{2} + \frac{10800}{x}

What is the extreme f(x)= 1/x ,[1,infinity ] ?
The extreme f(x)= 1/x ,[1,infinity ] is Maximum(1,1)