What is the extreme f(x,y)=6y^2+4x^2+4xy-16y+8x ?

The extreme f(x,y)=6y^2+4x^2+4xy-16y+8x is Minimum(-2,2)

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extreme f(x,y)=6y^2+4x^2+4xy-16y+8x

extreme points

f (x, y) = 6 y^{2} + 4 x^{2} + 4 x y - 16 y + 8 x

Minimum (- 2, 2)

Solution steps

Find the critical points:

(- 2, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = 12

D (x, y) = 80

Check the sign of at each critical point

Check critical point

(- 2, 2) :

Minimum

Minimum (- 2, 2)

y = (lo g_{10} (5 x)) + (3 I n x^{3})

x^{2} + \frac{640}{x}

f (x) = 2 x^{2} + \frac{10800}{x}

f (x, y) = x^{2} + y^{2} + 6 x - 4 y + 13

f (x) = (3 - 5 x) e^{2 x}

What is the extreme f(x,y)=6y^2+4x^2+4xy-16y+8x ?
The extreme f(x,y)=6y^2+4x^2+4xy-16y+8x is Minimum(-2,2)