What is the extreme f(x)=-14x^3+42x+42 ?

The extreme f(x)=-14x^3+42x+42 is Minimum(-1,14),Maximum(1,70)

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extreme f(x)=-14x^3+42x+42

extreme points

f (x) = - 14 x^{3} + 42 x + 42

Minimum (- 1, 14), Maximum (1, 70)

Solution steps

f^{'} (x) = - 42 x^{2} + 42

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- 14 x^{3} + 42 x + 42 : 14

Minimum (- 1, 14)

Plug

x = 1

into

- 14 x^{3} + 42 x + 42 : 70

Maximum (1, 70)

Minimum (- 1, 14), Maximum (1, 70)

f (x) = 15 x - x^{2} - 54

x^{2} + 2 x - x

y = 4 (x - 2) (x + 1)

12 + 6 x^{2} - x^{3}

f (x, y) = x^{4} + x^{2} - 6 x y + 3 y^{2}

What is the extreme f(x)=-14x^3+42x+42 ?
The extreme f(x)=-14x^3+42x+42 is Minimum(-1,14),Maximum(1,70)