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Popular >

extreme y=8+x-x^2

Solution

extreme points

y = 8 + x - x^{2}

Solution

Maximum (\frac{1}{2}, \frac{33}{4})

Solution steps

f^{'} (x) = - 2 x + 1

Find intervals:

Increasing

: - \infty < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

8 + x - x^{2} : \frac{33}{4}

Maximum (\frac{1}{2}, \frac{33}{4})

Popular Examples

extreme f(x)=-(x+2)^5(x-4)^4 extreme points

f (x) = - (x + 2)^{5} (x - 4)^{4}

extreme f(x,y)=x^3-3x+xy^2 extreme points

f (x, y) = x^{3} - 3 x + x y^{2}

extreme f(x)=3x^3+2x^2-10x+600 extreme points

f (x) = 3 x^{3} + 2 x^{2} - 10 x + 600

extreme 3x^2+3 extreme points

3 x^{2} + 3

extreme f(x)= 8/(x^2)+1/((40-x)^2)extreme points

f (x) = \frac{8}{x ^{2}} + \frac{1}{( 40 - x ) ^{2}}

Frequently Asked Questions (FAQ)

What is the extreme y=8+x-x^2 ?
The extreme y=8+x-x^2 is Maximum(1/2 , 33/4)