What is the extreme f(x)=x^2-3xy-y^2 ?

The extreme f(x)=x^2-3xy-y^2 is Saddle(0,0)

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extreme f(x)=x^2-3xy-y^2

extreme points

f (x) = x^{2} - 3 x y - y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 13

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x, y) = 4^{x - y - 7 x y} + 9 y^{2}

f (x) = x^{4} - 6 x^{2} + 2 x + 3

f (x, y) = (\frac{2}{6 ^{- x^{2} - y^{2} + 2}})

f (x, y) = 9 x^{2} + 9 x y + 6 y^{2} + 4 x y^{2} + 6 x^{2} y

f (x) = x^{\frac{6}{7}}, - 2 \leq x \leq 4

What is the extreme f(x)=x^2-3xy-y^2 ?
The extreme f(x)=x^2-3xy-y^2 is Saddle(0,0)