What is the extreme f(x,y)= 1/(e^{x-y)} ?

The extreme f(x,y)= 1/(e^{x-y)} is None

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extreme f(x,y)= 1/(e^{x-y)}

extreme points

f (x, y) = \frac{1}{e ^{x - y}}

None

Solution steps

Find the critical points:

None

\frac{1}{e ^{x - y}}

has no critical points, therefore there are no extreme points

None

f (x, y) = \frac{x ^{3}}{3} - 3 y^{2} - \frac{x ^{2}}{2} + 3 x y

y = \frac{( x + 3 ) ( x ^{2} - 2 r )}{x ^{3}}

14 x^{2} + \frac{3500}{x}

f (x, y) = x^{3} + y^{3} - 12 x - 3 y + 15

f (x) = x^{3} + 1 5^{2}

What is the extreme f(x,y)= 1/(e^{x-y)} ?
The extreme f(x,y)= 1/(e^{x-y)} is None