extreme f(x)=x^2-18x

Lösung

extrempunkte

f (x) = x^{2} - 18 x

Minimum (9, - 81)

Schritte zur Lösung

f^{'} (x) = 2 x - 18

Intervalle finden:

Absteigend

: - \infty < x < 9,

Ansteigend

: 9 < x < \infty

Stecke

x = 9

x^{2} - 18 x : - 81

Minimum (9, - 81)

e x t re m e f (x, y) = 400 - 49 x^{2} - 16 y^{2}

e x t re m e f (x) = \frac{3 x}{x ^{2} + 1}, - 4 \leq x \leq 4

e x t re m e f (x) = x^{3} + y^{3} - 3 x^{2} - 6 y^{2} - 9 x

e x t re m e 2 x^{3} - x^{2} - 4 x + 12

e x t re m e f (x) = x^{3} - \frac{3}{2} x^{2} - 6 x + 1